Pentax 12-660mm Zoom Lens

 

 

note: drawing not to scale

To identify an unknown subject 1.6m tall, the PSDB guidelines state that the subject should fill 120% of the height of the monitor screen. Therefore the subject to vertical field of view relationship is as per the diagram above. Based upon the Pentax C61233 (H55ZME-5F) lens, which has a vertical field of view on ½" format of 0.42° at 660mm, the following calculations apply:-

The 1.6m subject should fill 120% of screen. Therefore, actual field of view to be covered is 1.6 ÷ 1.2 = 1.33m

Tangent of ½ x angle of view = height of subject ÷ subject distance.

Therefore - Tangent of 0.21° = (1.33 ÷ 2) ÷ X. (Where X is the unknown subject distance).

Therefore - 0.0036652 = 0.665 ÷ X. Which implies that X = 0.665 ÷ 0.0036652

Therefore, the maximum distance at which a 1.6m person will fill 120% of the height of the monitor screen using the Pentax 12-660mm lens is 181.44m. (362.88m when using the built-in motorised 2x extender).

 

note: drawing not to scale

To recognise a known subject 1.6m tall, the PSDB guidelines state that the subject should fill 50% of the height of the monitor screen. Therefore the subject to vertical field of view relationship is as per the diagram above.

Based upon the Pentax C61233 (H55ZME-5F) lens, which has a vertical field of view on ½" format of 0.42° at 660mm, the following calculations apply:-

Tangent of ½ x angle of view = height of subject ÷ subject distance.

Therefore - Tangent of 0.21° = 1.6 ÷ X. (Where X is the unknown subject distance).

Therefore - 0.0036652 = 1.6 ÷ X. Which implies that X = 1.6 ÷ 0.0036652.

Therefore, the maximum distance at which a 1.6m person will fill 50% of the height of the monitor screen using the Pentax 12-660mm lens is 436.54m. (873.08m when using the built-in motorised 2x extender)

Note: The trigonometrical function of tangent states that the tangent of an angle in a right angled triangle is equal to the length of the opposite side divided by the adjacent side.